2n^2+118n-1800=0

Solution for 2n^2+118n-1800=0 equation:

2n^2+118n-1800=0

a = 2; b = 118; c = -1800;
Δ = b2-4ac
Δ = 1182-4·2·(-1800)
Δ = 28324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{28324}=\sqrt{4*7081}=\sqrt{4}*\sqrt{7081}=2\sqrt{7081}$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(118)-2\sqrt{7081}}{2*2}=\frac{-118-2\sqrt{7081}}{4}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(118)+2\sqrt{7081}}{2*2}=\frac{-118+2\sqrt{7081}}{4}
$